原式=[2x/(x²-4)-1/(x+2)]÷[(x-1)/(x-2)]={2x/[(x+2)(x-2)]-(x-2)/[(x+2)(x-2)]}×[(x-2)/(x-1)]=(2x-x+2)/[(x+2)(x-2)]×[(x-2)/(x-1)]=(x+2)/[(x+2)(x-2)]×[(x-2)/(x-1)]=1/(x-1)=1/(√3-1-1)=1/(√3-2)=(...