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化简sin8°+cos8°\sin8°-cos8°
人气:222 ℃ 时间:2020-02-05 15:49:20
解答
(sin8°+cos8°)/(sin8°-cos8°)
=(sin8°+cos8°)²/[(sin8°-cos8°)(sin8°+cos8°)]
=[1+sin16°]/[-(cos²8°-sin²8°)]
=-(1+sin16°)/cos16°
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