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lim(x→0)[sinx-x+x^3/6]/x^5 不用泰勒公式怎么做
人气:295 ℃ 时间:2020-01-29 12:26:57
解答
lim(x→0)[sinx-x+x^3/6]/x^5
=lim(x→0)[cosx-1+x^2/2]/(5x^4)
=lim(x→0)[-sinx+x]/(20x^3)
=lim(x→0)[1-cosx]/(60x^2)
=lim(x→0)(x^2/2)/(60x^2)
=1/120
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