1.不等式(x+2)/(x^2-3x+2)≥1的解集为?2.甲:{x|(2x+1)/x≤0}乙:x∈{x|log3(2x+1)_数学解答

1.不等式(x+2)/(x^2-3x+2)≥1的解集为?2.甲:{x|(2x+1)/x≤0}乙:x∈{x|log3(2x+1)

人气：250 ℃　时间：2020-05-12 11:59:27

解答

1.
(x+2)/(x^2-3x+2)>=1
(x+2)/(x^2-3x+2)-1>=0
(x+2-x^2+3x-2)/(x-1)(x-2)>=0
(-x^2+4x)/(x-1)(x-2)>=0
x(x-4)/(x-1)(x-2)请问怎么得到乙:0<2X+1<1,得到-1/20同时对数<0,就有2x+1<1