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数学
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函数y=2根号下-x²+2x+3的单调增区间为----?
人气:420 ℃ 时间:2019-08-19 15:37:06
解答
首先计算-x²+2x+3的单调区间,-x²+2x+3=-x²+2x-1+4=-(x-1)^2+4根号下面的数值越大开出来的就越大,所以求-(x-1)^2+4的单调增区间就可以-(x-1)^2+4≥0,-1≤x≤3,函数f(x)=-(x-1)^2+4在[-1,1]单调递...
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