(x-1)f(x-1分之x+1)+f(x)=x式子一
x不等于1
所以,用(x+1)/(x-1)来代替x,可得,
((x+1)/(x-1)-1)f(((x+1)/(x-1)+1)/ ((x+1)/(x-1)-1))+f((x+1)/(x-1))= (x+1)/(x-1)
整理得,
2/(x-1)f(x)+f((x+1)/(x-1))= (x+1)/(x-1),两边乘以(x-1)得,
2f(x)+(x-1)f((x+1)/(x-1))= (x+1) 式子二
式子二减去式子一可得,
f(x)=1,
思路是正确的,过程太烦了,你好好算算结果吧,也许不正确.