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求证sina+sinb+2sinasinbcos(a+b)=sin(a+b)
人气:228 ℃ 时间:2020-03-29 03:24:15
解答
sina+sinb+2sinasinbcos(a+b)=sina+sinb+2sinasinb(cosacosb-sinasinb) =sina+sinb+2sinasinbcosacosb-2sinasinb =sina-sinasinb+sinb-sinasinb+2sinasinbcosacosb =sina(1-sinb)+sinb(1-sina)+2sinasinbcosacosb =sinacosb+sinbcosa+2sinasinbcosacosb =(sinacosb+sinbcosa) =sin(a+b) 证毕,
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