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数学
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已知实数xy满足方程x^2+y^2-4x+1=0求y比x的最小值
人气:436 ℃ 时间:2019-12-09 09:02:39
解答
设y/x=k,即有y=kx代入方程中有:
x^2+k^2x^2-4x+1=0
(1+k^2)x^2-4x+1=0
判别式=16-4(1+k^2)>=0
1+k^2
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