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计算题半小时内我才采纳速度
(2又5/9+3又9/10-5.22)/(2又5/9-6又27/50+5.22)÷( (2006×0.4/2008×0.5)+1.6/2008 】
人气:373 ℃ 时间:2020-06-14 21:23:53
解答
(2又5/9+3又9/10-5.22)/(2又5/9-6又27/50+5.22)÷( (2006×0.4/2008×0.5)+1.6/2008 】
=(23/9+39/10-522/100)/(23/9-327/50+522/100)÷{[(2006x(2/5)/2008x(1/2)]+16/20080}
=(23/9-132/100)/(23/9-132/100)÷{[(4012/5)/2008x(1/2)]+16/20080}
=1÷{[(4012/10040x(1/2)]+16/20080}大哥没算完=1÷{[(4012/10040x(1/2)]+16/20080}

=1÷{[(4012/20080)]+16/20080}

=1÷{4028/20080}

=1÷{1007/5020}

=5020/1007
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