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已知tana=2,求3\4sin^2a+1\2+sin2a
写错了,是3\4sin^2a+1\2+sin2a
人气:359 ℃ 时间:2020-10-02 01:09:47
解答
3/(4sin^2a+1\2+sin2a)=3(sin^2a+cos^2a)/(4sin^2a+sin^2a+cos^2a\2+2sinacosa)=3(sin^2a+cos^2a)/(5sin^2a+cos^2a\2+2sinacosa)分子分母同时除以cos^2a=3(sin^2a/cos^2a+cos^2a/cos^2a)/(5sin^2a/cos^2a+cos^2a/cos...写错了,是3\4sin^2a+1\2+sin2a
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