如图1,一张矩形纸片ABCD,其中AD=8cm,AB=6cm,先沿对角线BD对折,点C落在C '的位置,BC'交AD于点G.
(1)求证:AG=C'G
(2)如图2,再折叠一次,使点D与点A重合,得折痕EN,EN交AD于点M,求EM的长.
![](http://a.hiphotos.baidu.com/zhidao/wh%3D600%2C800/sign=dac903d3a40f4bfb8c859652337f54c8/b03533fa828ba61ef018a4634134970a314e5983.jpg)
(1)证明:∵沿对角线BD对折,点C落在点C′的位置,∴∠A=∠C′,AB=C′D∴在△GAB与△GC′D中,∴△GAB≌△GC′D∴AG=C′G;(2)∵点D与点A重合,得折痕EN,∴DM=4cm,NM=3cm,∵EN⊥AD,∴MN= =3,由折叠及平行线的性质可...