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若3sinx-根3cosx=2根3sin(x-ρ)ρ∈(-π,π)则ρ=
人气:445 ℃ 时间:2020-09-20 04:16:15
解答
3sinx-√3cosx
=2√3(sinx*√3/2-cosx*1/2)
=2√3(sinxcosπ/6-cosxsinπ/6)
=2√3sin(x-π/6)
=2√3sin(x-ρ)
所以ρ=π/6
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