( x - 1 )" - 2( x" - 1 ) = 0( x - 1 )" - 2( x + 1 )( x - 1 ) = 0( x - 1 )[ ( x - 1 ) - ( 2x + 2 ) ] = 0( x - 1 )( x - 1 - 2x - 2 ) = 0( x - 1 )( -x - 3 ) = 0( x - 1 )( x + 3 ) = 0解方程得x1 = 1x2 = -3...