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已知tanx/2=根号5,求(1+sinx-cosx)/(1+sinx+cosx)的值!
人气:209 ℃ 时间:2019-08-19 21:47:14
解答
sinx = 2tan(x/2)/(1+tanx/2tanx/2) = 2*sqrt(5)/(1+5) = sqrt(5)/3cosx = (1-tanx/2tanx/2)/(1+tanx/2tanx/2) = -2/3(1+sinx-cosx)/(1+sinx+cosx)= (1+ sqrt(5)/3+2/3)/(1+ sqrt(5)/3-2/3)= sqrt(5)...
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