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数学
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当a.b为何值时,方程x方+2(1+a)x+(3a方+4ab+2)=0有实数根
人气:284 ℃ 时间:2019-09-29 04:15:46
解答
你题目出错了,应该还有4b^2
有实数根
4*(1+a)(1+a)-4(3a*a+4ab+4b*b+2)>=0
4+8a+4a*a-12a*a-16ab-16b*b-8>=0
-4a*a-16ab-16b*b-4a*a+8a-4>=0
-(2a+4b)平方-(2a-2)平方>=0
要使等式成立
只能2a+4b=0 2a-2=0
所以 a=1 b=-1/2
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