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lim(x->0+)(1/x)^tanx
人气:290 ℃ 时间:2020-02-03 00:43:00
解答
先取自然对数
lim(x->0+)ln(1/x)^tanx
=lim(x->0+)tanxln(1/x)
=lim(x->0+) -lnx/cotx
=lim(x->0+) -(1/x)/(-csc^2x)
=lim(x->0+) (six^2x)/x
=lim(x->0+) x^2/x
=0
lim(x->0+)(1/x)^tanx
=lim(x->0+)e^[ln(1/x)^tanx]
=e^[lim(x->0+)ln(1/x)^tanx]
=e^0
=1
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