【高一数学】简单的三角函数化简》》》1+sin2x+cos2x+1=√2sin(2x+π/4)+2_数学解答

【高一数学】简单的三角函数化简》》》
1+sin2x+cos2x+1
=√2sin(2x+π/4)+2

人气：299 ℃　时间：2020-04-05 11:40:24

解答

1+sin2X+cos2X+1=(sin2X+cos2X)+2
=√2[sin2X*√2/2 +cos2X*√2/2]+2
=√2(sin2X*cosπ/4 +cos2X*sinπ/4)+2
=√2sin(2X+π/4)+2