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若a2-3a+1=0,则2a5-5a4+2a3-8a2+3a+3=?很急、有木有人会、要有过程哈
人气:199 ℃ 时间:2019-10-23 06:02:02
解答
2a^5-5a^4+2a^3-8a^2+3a+3
=2a^5-6a^4+2a^3+a^4-3a^3+a^2+3a^3-9a^2+3a+3
=2a^3(a^2-3a+1)+a^2(a^2-3a+1)+3a(a^2-3a+1)+3
=0+0+0+3
=3
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