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约分x-(y-z)^2/(x+y)^2-z^2
人气:347 ℃ 时间:2020-06-20 06:59:52
解答
x-(y-z)^2/(x+y)^2-z^2=(x-y+z)(x+y-z)/(x+y-z)(x+y+z)=(x-y+z)/(x+y+z)
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