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约分:
(1)
−35a4b3c
21a2b4d

(2)
x2(y−z)2
(x+y)2z2
人气:297 ℃ 时间:2020-02-03 15:38:24
解答
(1)原式=
−7a2b3•5a2c
7a2b3•3bd
=-
5a2c
3db

(2)原式=
(x+y−z)(x−y+z)
(x+y+z)(x+y−z)
=
x−y+z
x+y+z
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