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(-2)^2003 *(-0.5)^2004=
(-2)^100+(-2)^101=?
人气:186 ℃ 时间:2020-06-24 23:34:17
解答
① (-2)^2003 *(-0.5)^2004
= (-2)^2003 *(-0.5)^2003 * (-0.5)
= [(-2) * (-0.5)]^2003 * (-0.5)
= 1^2003 * (-0.5)
= -0.5
② (-2)^100+(-2)^101
= (-2)^100+(-2)^100 * (-2)
= (-2)^100 * [1+(-2)]
= - 2^100
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