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当[(a+2b)/(a-2b)]=2时,代数式[(a+2b)/(a-2b)]+[(3a-6b)/(4a+8b)]的值为_______.
人气:416 ℃ 时间:2019-09-29 03:42:16
解答
因为[(a+2b)/(a-2b)]=2
所以[(a+2b)/(a-2b)]+[(3a-6b)/(4a+8b)]
=2+[3(a-2b)]/[4(a+2b)]
=2+3/4×(a-2b)/(a+2b)
=2+3/4×1/2
=2+3/8
=19/8
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