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当x=1,y=2,z=3时,求代数式3x²y-[2x²y-(2xyz-x²z)-4x²z]-2xyz的值
人气:144 ℃ 时间:2020-03-20 14:59:41
解答
3x²y-[2x²y-(2xyz-x²z)-4x²z]-2xyz
=3x²y-2x²y+2xyz-x²z+4x²z-2xyz
=x²y+3x²z
=x²(y+3z)
=1²*(2+3*3)
=11
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