一道物理题,(第九题)
人气:188 ℃ 时间:2020-04-02 18:06:24
解答
9、设湿沙含水x%m湿沙=100kgm水=xkgm干沙=100-x kgc水=4180J/(kg°C)c干沙=0.9*10³J/(kg°C)c湿沙=1.2*10³J/(kg°C)c干沙*(100-x)+c水*x=c湿沙*1000.9*1000(100-x)+4180*x=1200*10090000-900x+4180x=12000...
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