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lim(n^2(m/n-1/(n+1)-1/(n+2)-……-1/(n+m)))的值是多少 讲述一下思路
n→∞
人气:227 ℃ 时间:2020-02-03 13:46:30
解答
m/n-1/(n+1)-1/(n+2)-……-1/(n+m)
=[1/n-1/(n+1)]+[1/n-1/(n+2)]+.+[1/n-1/(n+m)]
=1/[n(n+1)]+2/[n(n+2)]+...+m/[n(n+m)]
所以当n→∞时
lim(n^2(m/n-1/(n+1)-1/(n+2)-……-1/(n+m)))
=lim{n^2/[n(n+1)]+2n^2/[n(n+2)]+...+m×n^2/[n(n+m)]}
=1+2+...+m
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