>
数学
>
等差数列中,a
1
+a
2
+a
3
=-24,a
18
+a
19
+a
20
=78,则此数列前20项和等于( )
A. 160
B. 180
C. 200
D. 220
人气:432 ℃ 时间:2019-09-09 18:37:21
解答
∵a
1
+a
2
+a
3
=-24,a
18
+a
19
+a
20
=78
∴a
1
+a
20
+a
2
+a
19
+a
3
+a
18
=54=3(a
1
+a
20
)
∴a
1
+a
20
=18
∴
S
20
=
20(
a
1
+
a
20
)
2
=180
故选B
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