> 数学 >
若a2=3a-1,则分式
2a5-5a4+2a3-8a 2
a2+1
的值是______.
人气:463 ℃ 时间:2019-08-18 11:31:47
解答
原式=
2a3(a2+1)-a2(5a2+8)
a2+1

=
2a3(3a-1 +1)-a2[5(3a-1)+8]
a2+1

=
2a3•3a-a2[15a+3]
a2+1

=
6(3a-1)2-(3a-1)[15a+3]
a2+1

=
(3a-1)[6(3a-1)-(15a+3)]
a2+1

=
(3a-1)(3a-9)
a2+1

=
9(3a-1)-30a+9
3a

=
-3a
3a

=-1.
故答案为:-1.
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