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求值域:Y=x/X+1,Y=根号下X+1,y=X+根号下2X+1,Y=2+根号下5+4X-X的平方
人气:145 ℃ 时间:2020-03-22 16:00:42
解答
Y=x/(x+1)=1-1/(x+1)定义域x+1≠0,x≠-1值域:1/(x+1)≠0y≠1y=√(x+1)定义域x+1≥0,x≥-1值域:y≥0y=x+√(2x+1)定义域2x+1≥0,x≥-1/2因为y=x和y=√(2x+1)在x≥-1/2都是增函数x=-1/2时,y=-1/2所以值域为y≥-1/2y...
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