1.设 x=logaM y=logaNM=a^x N=a^yMN=(a^x)*(a^y)=a^(x+y)两边取对数logaMN=x+y=logaM+logaN 2.这个是 logaM/N=logaM-logaN 设 x=logaM y=logaNM=a^x N=a^yM/N=(a^x)/(a^y)=a^(x-y)两边取对数得logaM/N=x-y=logaM-log...