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1-(a-b/a+2b)÷(a2-b2/a2+4ab+4b2),其中a=√2,b=1
人气:124 ℃ 时间:2020-04-07 16:21:26
解答
原式=1-(a-b)/(a+2b)÷(a+b)(a-b)/(a+2b)²
=1-(a-b)/(a+2b)×(a+2b)²/(a+b)(a-b)
=1-(a+2b)/(a+b)
=(a+b-a-2b)/(a+b)
=-b/(a+b)
=-1/(√2+1)
=-√2+1
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