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计算:定积分∫(在上9 ,在下 4)√x(1+√x)dx求详细过程答案,..
人气:305 ℃ 时间:2020-05-13 00:29:55
解答
∫(4→9)√x(1+√x)dx
=∫(4→9)(√x+x) dx
=[2/3·x^(3/2)+x²/2] |(4→9)
=[2/3·9^(3/2)+9²/2]-[2/3·4^(3/2)+4²/2]
=271/6
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