若幂函数y=(m2+3m-17)x4m−m2的图象不过原点,则m的值为______.
人气:163 ℃ 时间:2019-10-31 19:08:12
解答
∵幂函数y=(m
2+3m-17)
x4m−m2的图象不过原点,
∴
,解得m=-6.
故答案为:-6.
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