∴原式=
a2 |
2a2−b(a+b) |
b2 |
2b2−a(a+b) |
(a+b)2 |
2(a+b)2+ab |
=
2a2b+a3−2ab2−b3 |
(a−b)(2a+b)(2b+a) |
a2+b2+2ab |
2a2+2b2+5ab |
=
(a−b)(2ab+a2+b2+ab) |
(a−b)(2a+b)(2b+a) |
a2+b2+2ab |
2a2+2b2+5ab |
=
2ab+a2+b2+ab |
(2a+b)(2b+a) |
a2+b2+2ab |
(2a+b)(2b+a) |
=
2a2+2b2+5ab |
2a2+2b2+5ab |
=1.