方程2sin^2x-cosx+a-1=0
即a=-2sin²x+cosx+1
=-2(1-cos²x)+cosx+1
=2cos²x+cosx-1
=2(cosx+1/4)²-9/8
∵-1≤cosx≤1
∴当cosx=-1/4时,
2(cosx+1/4)²-9/8取得最小值-9/8
当cosx=1时,
2(cosx+1/4)²-9/8取得最大值2
∵方程有解,
∴a的范围是[-9/8,2]