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(a^4/3-8a^1/3b)/(4b^2/3+2三次根号ab+a^2/3)/(1-2三次根号b/a)*三次根号a
人气:455 ℃ 时间:2020-07-02 06:12:24
解答
(a^4/3-8³√ab)/(4b^2/3+2³√ab+a^2/3)/(1-2³√b/a)*³√a =³√a(a-8b)/(4b^2/3+2³√ab+a^2/3)/(1-2³√b/a)*³√a =³√a(³√a-2³√b)(a^2/3+2³√ab+4b^2...
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