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(3x^2-2y^2)^4x(2/3y^2-x^2)^2 ,其中3x^2-2y^2=2
人气:134 ℃ 时间:2020-04-06 19:31:00
解答
(3x^2-2y^2)^4x(2/3y^2-x^2)^2
=(3x^2-2y^2)^4x(2y^2-3x^2)^2/3^2
=(3x^2-2y^2)^6/3^2
=2^6/3^2
=64/9
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