利用一元二次方程一般形式ax²+bx+c=0(a≠0,b c为实数) 用配方法求证求根公式△=b²-4ac
利用一元二次方程一般形式ax²+bx+c=0(a≠0,b c为实数)
用配方法求证求根公式△=b²-4ac
人气:172 ℃ 时间:2019-11-14 23:43:51
解答
ax²+bx=-c
x²+bx/a=-c/a
x²+bx/a+b²/4a²=-c/a+b²/4a²
(x+b/2a)²=(b²-4ac)/4a²=[±√(b²-4ac)/2a]²
x+b/2a=±√(b²-4ac)/2a
x=-b/2a±√(b²-4ac)/2a
x=[-b±√(b²-4ac)]/2a
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