tanα=2
sinα/cosα=2
sinα=2cosα
sin²α+sinαcosα-2cos²α
=(sinα+2cosα)(sinα-cosα)
=(2cosα+2cosα)(2cosα-cosα)
=4(cosα)^2
=4*(1+cos2α)/2
=2+2cos2α
=2+2[1-(tanα)^2]/[1+(tanα)^2]
=2+2[1-2^2]/[1+2^2]
=2-6/5
=4/5