代数式2m=3n,则m/(m+n)-m/(m-n)-2n^2/(m^2-n^2)=
人气:115 ℃ 时间:2019-11-10 15:21:15
解答
m/(m+n)-m/(m-n)-2n^2/(m^2-n^2)= m(m-n)/(m^2-n^2)-m(m+n)/(m^2-n^2)-2n^2/(m^2-n^2)= (m^2-mn-m^2-mn-2n^2)/(m^2-n^2)= 2n(m+n)/(n+m)(n-m)= 2n/(n-m)2m=3n m=1.5n2n/(n-m)=-4
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