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已知AB=2,A-B=4,求(2ab^2+1/(a-b)^2)-(1+2a^2b/(b-a)^2)
人气:416 ℃ 时间:2020-06-10 12:28:01
解答
(2ab^2+1/(a-b)^2)-(1+2a^2b/(b-a)^2)
=(2ab^2+1-1-2a^2b)/(a-b)^2
=2ab(b-a)/(b-a)^2
=2ab/(b-a)
=4/-4
=-1
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