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观察下列等式:1×2=
1
3
×1×2×3
1×2+2×3=
1
3
×2×3×4
1×2+2×3+3×4=
1
3
×3×4×5
,…,照此规律,计算1×2+2×3+…+n(n+1)=______(n∈N*).
人气:309 ℃ 时间:2020-04-03 07:40:09
解答
1×2=
1
3
×1×2×3

1×2+2×3=
1
3
×2×3×4

1×2+2×3+3×4=
1
3
×3×4×5


照此规律,
1×2+2×3+…+n(n+1)=
1
3
n(n+1)(n+2)

故答案为:
1
3
n(n+1)(n+2)
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