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1×1/5+1/5×1/9+1/9×1/13+······+1/37×1/41=?递等式简便运算,
人气:297 ℃ 时间:2020-06-17 11:01:34
解答
1×1/5+1/5×1/9+1/9×1/13+······+1/37×1/41
=1/4×(1-1/5)+1/4×(1/5-1/9)+1/4×(1/9-1/13)+……+1/4×(1/37-1/41)
=1/4×(1-1/5+1/5-1/9+1/9-1/13+……+1/37-1/41)
=1/4×(1-1/41)
=1/4×40/41
=41分之10
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