f(x）=√3sinxcosx-cos^2x+1/2=√3/2*sin2x-(cos2x+1)/2+1/2=√3/2*sin2x-1/2*cos2x=sin(2x-π/6)（1）求函数f(x）的最小正周期T=2π/2=π（2）因0≤x≤π/4所以-π/6≤2x-π/6≤π/3-1/2≤sin(2x-π/6)≤√3/2函数f...