=1/[(x-a)(x-b)]²=[1/(x-a)-1/(x-b)]²/(a-b)²={1/(x-a)²+1/(x-b)²-2/[(x-a)(x-b)]}/(a-b)²={1/(x-a)²+1/(x-b)²-2/[(x-a)(a-b)]+2/[(x-a)(a-b)]}/(a-b)²；∫dx/[(x-a)(...