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分解因式:x2-y2-2y-1=______.
人气:235 ℃ 时间:2020-04-17 23:53:06
解答
x2-y2-2y-1,
=x2-(y2+2y+1),
=x2-(y+1)2
=(x+y+1)(x-y-1).
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