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(x-2-(5/x+2))÷x-3/2x+4,其中x=√2-3
人气:404 ℃ 时间:2020-04-14 02:38:50
解答
原式=[(x-2)(x+2)-5]/(x+2)*(2x+4)/(x-3)
=(x²-9)/(x+2)*(2x+4)/(x-3)
=(x+3)(x-3)/(x+2)*2(x+2)/(x-3)
=2x-6代值是多少哦,对不起原式=2x-6=2√2-6-6=2√2-12
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