x²-2(1+√2)x+2√2＝0
→[x²-2(1+√2)x+(1+√2)²]＝(1+√2)²-2√2
→[x-(1+√2)]²＝3
∴x1＝1+√2+√3,x2＝1+√2-√3.太感谢了