为免去讨论的过程
由于:f(1-m)>f(2m)
且偶函数f(x)在[0,+∞ )上单调递增
则有:
|1-m|>|2m|
则：(1-m)^2>(2m)^2
m^2-2m+1>4m^2
3m^2+2m-1