若X∈(-∞,1)则函数Y=X²-2X+2/2X-2=[（x-1）²+1]/2(x-1)=(x-1)/2+1/2(x-1)∵x∈(-∞,1)∴1-x＞0;∴(x-1)/2+1/2(x-1)≥2√(x-1)/2×1/2(x-1)=2×1/2=1;所以值域为[1,+∞)很高兴为您解答,skyhunter002为您答...