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用换底公式求log(2)25乘log(3)4乘log(5)9的值
人气:395 ℃ 时间:2020-01-30 15:44:32
解答
log(2)5=log(3)5/log(3)2
log(5)3=log(3)3/log(3)5=1/log(3)5
log(2)25乘log(3)4乘log(5)9
=(2*log(2)5)(2*log(3)2)(2*log(5)3)
=8*log(3)5*log(5)3
=8*log(3)5*1/log(3)5
=8
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